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# Draw the graph of y = sin(2x - pi/3)

Question: Graw the graph of the function y = sin(2x - pi/3)

- Solution:
- Step1: draw the graph of y = sin(2x)
- Compare the standard form of the sine function, y = A sin(Bx + c)
- For, y = sin(2x), A = 1, B = 2, and C = 0
- The period (T) of y = sin(2x) is T = 2pi/B = 2pi/2 = pi
- so, the amplitude of y = sin(2x) is 1 and period is pi.
- Use the five points method to draw the graph of y = sin(2x)
- If x = 0, y = sin(2x) = sin(0) = 0
- If x = pi/4, y = sin(2x) = sin(2 × pi/4) = sin(pi/2) = 1
- If x = pi/2, y = sin(2x) = sin(2 × pi/2) = sin(pi) = 0
- If x = 3pi/4, y = sin(2x) = sin(2 × 3pi/4) = sin(3pi/2) = -1
- If x = pi, y = sin(2x) = sin(2pi) = 0

x | 0 | pi/4 | pi/2 | 3pi/4 | pi | |
---|---|---|---|---|---|---|

y | 0 | 1 | 0 | -1 | 0 |

- Step2: shift the graph of y = sin(2x) right pi/6 units to get the graph of y = sin(2x - pi/3).

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