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# Graph of Sine function example 1

### Draw Sine function example 1

### Sine function example 2

### Function example 3

- Question
- Draw the graph of y = 1 + sin(x - pi/2)

- Solution:
- Step 1. Draw the graph of y = sin x
- Step 2. Move the graph one unit up because it is y = 1 + sin(x - pi/2)
- Step 3. Move the graph toward right direction pi/2 units because it is y = sin(x - pi/2) + 1

- Question:
- In the interval x >= 0 and x <= pi, what is the value of x when sin(6x) passes the x-axis the fifth time?

- Solution
- For y = sin(6x), B = 6, period = 2pi/B = 2pi/6 = pi/3. So the graph of y = sin(6x) passes the x-axis at 0, pi/6, pi/3, pi/2, 2pi/3, 5pi/6, pi. So that, in the interval [0, pi], x = 5pi/6 is the fifth time when the curve passes the x-axis.

- Question:
- If f(x) = 3x
^{2}- 2x + 1, what value of x will make f(x) a minimum?

- Solution:
- f(x) = 3x
^{2}- 2x + 1 - = 3[x
^{2}- (2/3)x + 1/3] - = 3[x
^{2}- (2/3)x + (1/3)^{2}- (1/3)^{2}+ 1/3] - = 3[x
^{2}- (2/3)x + 1/9 - 1/9 + 1/3] - = 3[x
^{2}- (2/3)x + 1/9 - 1/9 + 3/9] - = 3[x
^{2}- (2/3)x + 1/9 + 2/9] - = 3[(x - 1/3)
^{2}+ 2/9]

- since (x - 1/3)
^{2}>= 0, so the smallest value of (x - 1/3)^{2}is 0 - thus, x = 1/3 make f(x) a minimum.
- so when x = 1/3, f(x) has the minimum value, and f(1/3) = 3 × 2/9 = 6/9 = 2/3.

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