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Number problem solving 4

Question:
Three consecutive integers are listed in increased order. If their product is 336. What is the second integer in the list?
Solution:
Use the factoring method to find these numbers.
336 ÷ 2 = 168
168 ÷ 2 = 84
84 ÷ 2 = 42
42 ÷ 2 = 21
21 ÷ 3 = 7
so 336 = (2)(2)(2)(2)(3)(7) = 23 × 2 × 3 × 7
since 23 = 8
so, 336 = 8 × 6 × 7
the list of the numbers in increasing order is 6, 7, 8
So, the second integer in the list is 7.

The product of three consecutive integers is 336. Factoring the number 336, find that 6 × 7 × 8 is equal to 336. So, the three integers in increase order are 6, 7, and 8. The second integer is 7.