- Example of number problem solving question 2
- Question:
- The product of two consecutive positive number is 240. Find these two numbers.

- Solution:
- 240 ÷ 2 = 120
- 120 ÷ 2 = 60
- 60 ÷ 2 = 30
- 30 ÷ 2 = 15
- 15 ÷ 3 = 5
- so 240 = (2)(2)(2)(2)(3)(5) = 2
^{4}× 3 × 5 - since 2
^{4}= 16 and 3 × 5 = 15 - so 240 = 15 × 16
- so the two consecutive positive numbers are 15 and 16.

Use the quadratic equation to solve this problem. Because these two numbers are consecutive numbers, so if the first number is x, then he second number is (x + 1). Because the product of the two consecutive number is
240, so x(x + 1) = 240. Then x^{2} + x = 240. Since the equation is two degree of the variable x, so move the number 240 to the left side of the equation.
We get the quandratic equation: x^{2} + x - 240 = 0. The leftside of the equation can be factored as (x - 15)(x + 16) = 0. Then (x - 15) = 0 or (x - 16) = 0.
Thus we get two solutions x_{1} = 15 and x_{2} = 16. So these two consecutive number are 15 and 16.